((2x-3)/(2(2x^2-3x)))=0

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Solution for ((2x-3)/(2(2x^2-3x)))=0 equation: 


D( x )

2*(2*x^2-(3*x)) = 0

2*(2*x^2-(3*x)) = 0

2*(2*x^2-(3*x)) = 0

2*(2*x^2-3*x) = 0

2*x^2-3*x = 0

x*(2*x-3) = 0

2*x-3 = 0 // + 3

2*x = 3 // : 2

x = 3/2

x*(x-3/2) = 0

2*x*(x-3/2) = 0

( 2 )

2 = 0

x belongs to the empty set

( x-3/2 )

x-3/2 = 0 // + 3/2

x = 3/2

( x )

x = 0

x in (-oo:0) U (0:3/2) U (3/2:+oo)

(2*x-3)/(2*(2*x^2-(3*x))) = 0

(2*x-3)/(2*(2*x^2-3*x)) = 0

2*x^2-3*x = 0

x*(2*x-3) = 0

2*x-3 = 0 // + 3

2*x = 3 // : 2

x = 3/2

x*(x-3/2) = 0

(2*x-3)/(2*x*(x-3/2)) = 0

2*x-3 = 0 // + 3

2*x = 3 // : 2

x = 3/2

x in { 3/2} 

x belongs to the empty set

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